Question

how many three-digit number are divisible by 6 in all

Answer 1

minimum 3 digit number = 100
minimum 3 digit number divisible by 6 =102
maximum 3 digit number = 999
maximum 3 digit number divisible by 6 = 996
now,A/q
first term = 102
last term = 996
common difference = 6
as, l = a + (n -1) d
⇒996 = 102 + (n -1 )6
⇒996 - 102 = (n -1) 6
⇒894 = (n -1 ) 6
⇒(n -1) = 894/6 = 149
⇒n = 149 +1 = 150
total number of terms is 150