how many three digit number are divisible by 7
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105, 112,119,_____994
a=105 d=7 an=994 an=a+(n-1)d
994=105+(n-1)7 994-105=(n-1)7 889=(n-1)7 889÷7=(n-1) 127=(n-1) 127+1=n 128=n n=128 is the answer
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