How many three digit number are divisible by 7?
See this is the question from AP and I want to know that how will we find a ∨ n ....so anyone who has the solution then please respond to this question !!!! I need the answer soon !
Answers
Answered by
18
first three digit number divisible by 7(a) = 105
last three digit number divisible by 7 (l or an) = 994
an = a + (n - 1)d
994 = 105 + (n-1)7
889 = 7(n-1)
n-1 = 127
n= 128
hence, there are 128 three digit numbers divisible by 7
last three digit number divisible by 7 (l or an) = 994
an = a + (n - 1)d
994 = 105 + (n-1)7
889 = 7(n-1)
n-1 = 127
n= 128
hence, there are 128 three digit numbers divisible by 7
Anonymous:
How have u found last three digit no.?
there is two ways to find last number , first one is trial and error method and other one is to divide 1000 by 7 and subtract reminder from 1000.
Oh thanks that is what I was asking
the same answer is at http://www.meritnation.com/ask-answer/question/how-many-3-digit-number-are-divisible-by-7/math/1829650
I think this is copied with the web i did because the date is given there it was written in8/2/2015
your welcome!
I'd not read the whole question...
may be possible because it is the most common and easiest way to solve this type of question..
Answered by
4
128 three digit number is divisible by 7
1000 divided by 7 is 142 with remainder 6.
So there are 142 positive integers less than 1000 that are divisible by 7.
100 divided by 7 is 14 with remainder 2.
So there are 14 positive integers less than 100 that are divisible by 7.
therefore, are 142 - 14 = 128 three digit numbers that are divisible by 7.
1000 divided by 7 is 142 with remainder 6.
So there are 142 positive integers less than 1000 that are divisible by 7.
100 divided by 7 is 14 with remainder 2.
So there are 14 positive integers less than 100 that are divisible by 7.
therefore, are 142 - 14 = 128 three digit numbers that are divisible by 7.
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