How many three digit number can be formed by using the digits 4, 5, 6, 7, 8, 9 if the repetition of digit is not allowed?
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HELLO DEAR,
(4,5,6,7,8,9) there are 6 no.
if the repeatition of digit is not allowed
then in
in 1 digit = 6ways
in 2 digit = 5ways
in 3 digit = 4ways
hence the no. of 3digit without repetition = 6×5×4 = 120 ways
I HOPE ITS HELP YOU DEAR,
THANKS
(4,5,6,7,8,9) there are 6 no.
if the repeatition of digit is not allowed
then in
in 1 digit = 6ways
in 2 digit = 5ways
in 3 digit = 4ways
hence the no. of 3digit without repetition = 6×5×4 = 120 ways
I HOPE ITS HELP YOU DEAR,
THANKS
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