how many three digit number is devisible by 9
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Using A.P,
108, 117,.....999
a = 108
d = 9
an = 999
an = a + (n-1) d
999= 108 + (n-1)9
999=108 + 9n - 9
999 = 99 + 9n
900 = 9n
n= 100
108, 117,.....999
a = 108
d = 9
an = 999
an = a + (n-1) d
999= 108 + (n-1)9
999=108 + 9n - 9
999 = 99 + 9n
900 = 9n
n= 100
aryan7758:
thanx
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