Question

How many three digit number which leave remainder 2 when divided by 5

Answer 1

Answer:

hy

Step-by-step explanation:

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Three digit numbers which leave the remainder 2 when divided by 5 are 102, 107, 112,117......, 997

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Answer 2

Answer: 180

Step-by-step explanation:

This can be solved by using Arithmetic Progression

Smallest 3 digit number that leaves remainder 2 when divided by 5 is 102.

Largest 3 digit number that leaves remainder 2 when divided by 5 is 997.

Now we can apply AP as the common difference in each of the terms is 5.

           L=a + (n-1)d         where L=last term      a=First term

                                        d=Common Difference             n=Number of terms

  L=997        a=102      d=5

 997=102+(n-1)5

 895=(n-1)5

 n-1=179

 n=180

Therefore there are 180 such 3 digit numbers.