Question

How many three digit numbers are divisible by 11?Also find the middle term

Answer 1

Heya user ,
Here is your answer !!

The first 3-digit number divisible by 11 is 110 .
The last 3-digit number divisible by 11 is 990 .

So , the A.P. series is 110 , 121 , .... 990 .

Common difference = 11 .

an = a1 + ( n - 1 ) d
=> 990 = 110 + ( n - 1 ) 11
=> 880 = ( n - 1 ) 11
=> 80 = ( n - 1 )
=> 81 = n .

So , number of 3 digit numbers divisible by 11 is 81 .

Now , the middlemost term is the 41th term .

So , a41 = a1 + ( n - 1 ) d [ where n = 41 ]
=> a41 = 110 + (41-1)*11
=> a41 = 110 + ( 11*40 )
=> a41 = 110 + 440
=> a41 = 550 .

So , the middlemost term of this A.P. series is 550 .

Hope it helps !!

Answer 2

Hii friend,

here is your answer...