Question

How many three-digit numbers are divisible by 7?
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Answer 1

Answer:

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numbers begin from 105 .......994

here a= 105

l= 994

n=?

d= 7

so

994 = 105+(n-1) 7

= 105+7n-7

994= 98+7n

994-98 = 7n

896/7 = n

n= 128

so 128 three digit numbers are divisible by 7

Answer 2

$\large{ \underline{ \underline{ \underline{ \boxed{ \frak{ \red{Answer :-}}}}}}}$

numbers begin from 105 .......994

here a= 105

l= 994

n=?

d= 7

so

994 = 105+(n-1) 7

= 105+7n-7

994= 98+7n

994-98 = 7n

896/7 = n

n= 128

so 128 three digit numbers are divisible by 7