Question

how many three digit numbers are divisible by 7 in arthematic progression

Answer 1

Hey user !!

Here is your answer !!

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Now the AP will be 105 ,112 ,994

a=105

d=7

l=994

By applying the formula

an=a+(n-1)d

994 = 105 + (n-1) 7

889 = 7 (n-1)

889/7 = n-1

127 = n-1

127 + 1= n

128 = n

Hence 128 numbers are divisible by 7

Hope it is satisfactory :-)

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Answer 2

heya mate !!

here is your answer :-

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ques. = how many three digits number are divisible by 7.

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The smallest three digit number which is divisible by 7 = 105

And the greatest number which is divisible by 7 = 994

So , A.P. will be = 105 , 112 , 119........994

Common difference = 7

Last number = 994

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On putting values ,

An = a + ( n - 1 ) d

994 = 105 + ( n - 1 ) 7

994 - 105 = 7n - 7

889 = 7n - 7

889 + 7 = 7n

896 = 7n

n = 128

So, the total three digit numbers which is divisible by 5 is 128.

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hope it helps

thanks for asking

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