Question

how many three digit numbers are divisible by 9

Answer 1

100 three digit numbers are divisible by 9 .


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Answer 2

I have different solution.

The lowest number greater than a hundred and divisible by 9 is 108...
the largest number divisible by 9 and less than a thousand is 999...

we use this formula...

T = A + (n-1)*d

T is the nth term in an arithmetic sequence
A is the first term in an arithmetic sequence
n is the number of terms
d is the common difference

you are asking for "the number of 3 digit numbers divisible by 9" or numbers that are greater than 100 but less than 1000 that are divisible by 9

so...

we are looking for the number of terms given

first term(A) = 108
last term(T) = 999
common difference(d) = 9

we subtitute the given values
999 = 108 + ( n - 1 ) * 9

we then solve...
999 = 108 + ( n - 1 ) * 9
999 - 108 = ( n - 1 ) * 9
891 = ( n - 1 ) * 9
( 891 ) / 9 = [ ( n - 1 ) * 9 ] / 9
99 = n - 1
99 + 1 = n
100 = n

therefore...
there are 100 3-digit numbers divisible by 9.

i have worked hard to answer this..plzz mark as a brainliest answer.