How many three digit numbers are such that when divided by 7 leaves a remainder 3 in each case?
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2
Answer:
128
Step-by-step explanation:
you how to make an arithmetic progression about 3 digit numbers which leaves reminder 3 after divded by 7
101,108.................997
a=101
d=7
an(last number)=997
then you have to use this formula
an=a+(n-1)d
and you will get the answer
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