how many three digit numbers are there divisible by 3 find its sum
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300.
Step-by-step explanation:
First term divisible by 3 is 102
Last term divisible by 3 is 999
Common Difference is 3
Let there be n terms. This means that term n of this AP is 999.
Tn = a+(n-1)d
999 = 102+(n-1)3
897 = 3n-3
900 = 3n
n = 300
Thus, there are 300 three digit numbers divisible by 3.
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