Question

How many three-digit numbers are there, which leave a remainder 3 on
division by 7?
5:05​

Answer 1

Answer:

there are 129 numbers between 100 and 999 which are exactly divisible by 7 and leaves the remainder 3.

Step-by-step explanation:

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Answer 2

First 3 digit number is 100

When we divide 100 by 7 we get remainder 2.

So 101 is the first number where we get 3 as remainder when divided by 7.

So the next number is 7 more than 101.It is 108 and so on.

101,108,115,.........997

Now it is an AP.

a = 101

d = 7

an = 997

n = ?

an=a+(n-1)d

997 = 101+ (n - 1) 7

997- 101 = ( n-1 ) 7

896 = (n-1) 7

n-1 = 896 / 7

n-1 = 128

n = 128 + 1 = 129.

So the answer is 129.