how many three digit numbers can be formed by using each one of digit 2,3,5,7,9 only once?
Answers
Answered by
1
Answer:
number had 5 distinct digits I.e. n = 5
p(5,5) ways
p(5,5)=5!
= 5*4*3*2*1 = 60
Answer :60
Answered by
1
The number of three-digit numbers formed by using each digit 2,3,5,7,9 only once is 60.
Given,
The digits = 2,3,5,7 and 9.
To Find,
The number of three digits that can be formed.
Solution,
In this question, the digits are only used once,
It means that they are not repeating and will only occur once in every place of the number.
So, there are 5 digits,
2,3,5,7, and 9.
The number of ways to form a three-digit number will be ⁵P₃.
So, ⁵P₃
= 5 × 4 × 3
= 60 ways.
The number of three-digit numbers formed by using each digit 2,3,5,7,9 only once is 60.
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