Math, asked by mswami72, 6 months ago

How many three digit numbers can be formed using the digits 1,2,3,4,5,6,7 and 8 without repeating the digits and such that the tens digit is greater than the hundreds digit and less than the units digit?

A.
48

B.
56

C.
64

D.
72​

Answers

Answered by amitnrw
0

Given :  three digit numbers can be formed using the digits 1,2,3,4,5,6,7 and 8 without repeating the digit

Tens digit is greater than the hundreds digit and less than the units digit?

To Find : How many such numbers are possible

Solution:

Number is ABC

A < B < C

A = 1   B = 2  C  can be in 6 ways    ( 3 to 8)

A = 1   B = 3  C can be in 5 ways    ( 4 to 8)  

A = 1  B =7    C  can be in 1  ways  

Hence 6 + 5 + 4 + 3 + 2 +  1  = 21

if A = 2   Then 5 + 4 + 3 + 2 +  1  = 15

if A = 3  Then    4 + 3 + 2 +  1  = 10

if A = 4  Then  3 + 2 + 1 = 6 ways

if A = 5 then 2 + 1 = 3 ways

if A = 6 then   1  way

Hence total  = 21 + 15 + 10 + 6 + 3 + 1  =  56

Hence 56 such numbers are possible

Learn More:

brainly.in/question/20707237

00) All numbers which are divisible by 8 must also be divisible by 4 ...

brainly.in/question/17508568

how many three digit numbers which are neither divisible by 4 nor 5 is

brainly.in/question/13181275

Answered by BeccarPexity
0

\huge\fcolorbox{red}{red}{\color{lime}{Aɴsᴡᴇʀ❥࿐}}

Given :  three digit numbers can be formed using the digits 1,2,3,4,5,6,7 and 8 without repeating the digit

Tens digit is greater than the hundreds digit and less than the units digit?

To Find : How many such numbers are possible

Solution:

Number is ABC

A < B < C

A = 1   B = 2  C  can be in 6 ways    ( 3 to 8)

A = 1   B = 3  C can be in 5 ways    ( 4 to 8)  

A = 1  B =7    C  can be in 1  ways  

Hence 6 + 5 + 4 + 3 + 2 +  1  = 21

if A = 2   Then 5 + 4 + 3 + 2 +  1  = 15

if A = 3  Then    4 + 3 + 2 +  1  = 10

if A = 4  Then  3 + 2 + 1 = 6 ways

if A = 5 then 2 + 1 = 3 ways

if A = 6 then   1  way

Hence total  = 21 + 15 + 10 + 6 + 3 + 1  =  56

Hence 56 such numbers are possible

Learn More:

brainly.in/question/20707237

00) All numbers which are divisible by 8 must also be divisible by 4 ...

brainly.in/question/17508568

how many three digit numbers which are neither divisible by 4 nor 5 is

brainly.in/question/13181275

Similar questions