Question

How many three-digit numbers can we form from the digits 1 2 3 4 5 so that the digits 2 and 3 do not meet in the same number ? with explain please

Answer 1

Step-by-step explanation:

i help you i looking my notes

Answer 2

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• This answer is for no repetition number

$\mathbf{\underline{solution}}$

• total number of ways for selecting 3 number
• 5P3 = 5×4×3= 60

• Find number of 3 digit which have 2 and 3 beside
• _ _ _(2,3,??) 3 way
• _ _ _(??,2,3) 3 way
• _ _ _(3,2,??) 3 way
• _ _ _(??,3,2) 3 way
• total ways = 3×4 = 12

$\mathbf{\bold{answer \: = \: 60 - 12 = 48}}$

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