How many three-digit numbers divisible by 3 may be formed out of the digits 2, 3, 4 and 6 if the digits are not to be repeated? Select one:
a. 36
b. 24
c. 6
d. 12?
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The digits which can be used: 2, 3, 4, 6
Sum of digits = 2 + 3 + 4 + 6
= 15
Now, 15 is divisible by 3 so all the digits can be used to form a 3 digit number which will be divisible by 3
So, Choice for the first digit = 4
Since, No repetition is allowed so choice for the second digit = 3
Also, Choice for the third digit = 2
Now, Number of required three digit numbers = 4 × 3 × 2
= 24
Therefore, The correct answer is B. 24
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