How many three digit numbers is there such that when middle digit removed they become a two digit number is 1/9 of the three digit number
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Let the 3 digit number be: XYZ.
As per the question, we have to find the divisibility of number P (let),
P=(100X+10Y+Z)(X+Y+Z)
P=(99X+9Y)
P=9(11X+Y)
which is divisible by 9.
So, if the sum of three digit number is subtracted from the number. The resulting number is always divisible by 9
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