how many three digit of number are divisible by 3 or 5
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Step-by-step explanation:
- Assuming that you meant integers evenly divisible by 3 and 5 (without a remainder)
- 3 and 5 are prime numbers so any number evenly divisible by both is evenly divisible by their product, 15.
- For three digit integers, that would be all multiples of 15 from 7 x 15 to 66 x 15, or 60 multiples of 15 from 105 to 990.
- On the other hand, if you are considering any real number with three digits and allowing remainders as a literal9 interpretation of your question suggests, then an infinite collection of real numbers from -999 to -100, -9.99 to -9.91, -9.89 to -8.81, etc, -.001 to - .999, +001 to + .999, and +100 to 999 fulfills the requirement.
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