how many three digits are divisible by 7
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105, 112, 119,......994
a=105, d= 7
994 = a+(n-1)d
994= 105+(n-1)7
994 - 105 = (n-1)7
889 = (n-1)7
n-1= 889÷7
n-1= 127
n= 128
a=105, d= 7
994 = a+(n-1)d
994= 105+(n-1)7
994 - 105 = (n-1)7
889 = (n-1)7
n-1= 889÷7
n-1= 127
n= 128
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