Math, asked by tripler050909, 22 hours ago

how many three digits multiple of 3 can be written using number 1,3,5,9 if all digits are difference

Answers

Answered by supriyanaik620250
7

A three digit number is to be formed from given 9 digits 1,2,3,4,5,6,7,8,9.

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HTO

⇒Now, there are 9 ways to fill Ones place.

⇒Since repetition is not allowed, so Tens place can be filled by the remaining 8 digits.

So, tens place can be filled in 8 ways.

⇒Similarly, to fill Hundreds of places, we have 7 digits remaining.

So, hundreds can be filled by 7 ways.

⇒So, the required number of ways in which three-digit numbers can be formed from the given digits is 9×8×7=504

Answered by minku8906
4

The response is 12.

Given:

1,3,5,9 are the number.

To Locate:

1) The number 1,3,5,9 can be used to create three-digit multiples of three.

2) A sum of numbers must divide by three in order for it to be a multiple of three.

3) Thus, three-digit numbers that can be divided by three are as 1+3+5=9, which is divisible by 3, we get 135

4) 153 as 1+3+5=9 which is divisible by 3

5) 315 because 1+3+5=9 and 3 is a divisor of 9.

6) 351 since 1+3+5=9, which may be divided by 3,

7) 513 because 1+3+5=9 and 3 is a divisible number

8) 531 because 1+3+5=9 and 3 is a divisor

9) 159 as 1+5+9=15 which is divisible by 3

10) 195 is divisible by 3 since 1+5+9=15.

11) 519 since 1+5+9=15, which can be divided by 3,

12) 591 as 1+5+9=15 which is divisible by 3

13) As 1+5+9=15, which is divisible by 3, the number 915

14) 951 since 1+5+9=15, which can be divided by 3,

Therefore, there are 12 three-digit numbers which are multiples of 3.

Hence answer is 12.

#SPJ2

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