Question

how many three figit natural number are divisible by 5. also find the sum of all the numbers
plzz solve this wuestion fast i will mark you as brainlist

Answer 1

heres the answer hope it helps you

Answer 2

 How many three digit numbers are divisible by 5?

A.P=100,105,110,………..,995

Therefore,a=100

d=5

a+(n-1)d=995

100+(n-1)(5)=995

(n-1)(5)=895

(n-1)=179

n=180

Therefore ,there are 180 three digit numbers which are divisible by 5
Assuming we are restricting ourselves to positive integers (if we included negative integers, the sum would trivially be 0), the smallest such number is 100. The largest is 995.

100+105+110+...+990+995100+105+110+...+990+995

=5(20+21+22+...+198+199)=5(20+21+22+...+198+199)

=5((199)(200)2−(19)(20)2)=5((199)(200)2−(19)(20)2)

=5(19900−190)=5(19900−190)

=5(19710)=5(19710)

=98550