Question

how many tiles 40 cm2 in area will be required to pave to foot path 1m wide carried round the outside of a grass plot 28m long and 18m wide?

Answer 1

Answer:we calculate the area of the rectangular plot

Ap=b×h= 25 ×13 m =325 m²

we calculate th length of outside rectangle :

B= 25 +2 +2 =29 m,

we calculate the breadth of outside rectangle:

H = 13 +2 +2 = 17 m

we calculate the area of outside rectangle:

Ar =B×H=29 x 17  = 493 m²

we calculate the area area of foot path :

A=Ar-Ap= 493 - 325 = 168 m²

we have that:

Atiles= 400 cm²=0,04 m²

we calculate the number of tiles required to cover the footpath :

n= A/Atitles=168/0,04=4200  tiles

Answer 2

SOLUTION:-

⚫Length of the plot= 28m

⚫Breadth of the plot= 18m

Therefore,

Area of the rectangular plot= 28m×18m

=) 504m²

Length of outside rectangle=28+2=30m

Breadth of outside rectangle=18+2=20m

Area of outside rectangle= 30m × 20m

=) 600m²

So,

Area of foot path:

=) 600m² - 504m²

=) 96m²

Convert in cm²

=) 96 ×100 × 100 =) 960000cm²

Now,

Area of square tile = 40cm² [given]

Number of tiles required;

=) 960000/40

=) 24000 tiles needed.

Hope it helps ☺️