How many tiles are required to cover a floor a length 6m and breadth 4m, if the area covered by each tile is 400 sq. cm
Answers
Answered by
5
Answer:
600 tiles
Step-by-step explanation:
Length of floor = 6m
Breadth of floor = 4m
Area of floor = (LENGTH x BREADTH)
= 6 x 4
= 24m^2 = 240000cm^2
Area of one tile = 400cm^2
No. of tiles required = 240000 / 400
= 600 tiles
Answered by
3
Answer:
600
Step-by-step explanation:
Length=6m=600cm
Breadth=4m=400cm
Area of the tile = 400 sq. cm
Area of floor = Length * Breadth
= 600*400
=240000 sq.cm
No of tiles = Area of floor /Area of tiles
= 240000/400
=600
Total number of tiles are 600.
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