Question

how many tiles are required to cover a floor of length 6m and breadth 4m if the area covered by each tile is 400sq. cm​

Answer 1

$\sf\huge\green{Question:}$

How many tiles are required to cover a floor of length 6m and breadth 4m if the area covered by each tile is 400sq. cm ?

$\sf\red{Answer:}$

600 tiles are required.

$\sf\pink{Given:} Length~ of ~floor = 6m =600 cm \\ \\ \sf breadth~ of ~floor = 4m=400 cm \\ \\ \sf Area~of ~each ~tile= 400 sq. cm$

$\sf\pink{To~find:}No \: of \: tiles\: required\: to \: cover\: the\: floor$

$\sf\pink{Solution:}Area ~of~floor= L \times B\\ \\ \implies 600\times 400 \\ \\ \implies 2,40,000cm^2 \\ \\ \sf Area~requires ~by~one~tile=400 sq. cm \\ \\ \sf No~ of ~tiles ~requires ~For~floor=\dfrac{2,40,000}{400} \\ \\ \implies 600$

$\sf\orange{Hence,~600~tiles~are~required}$

Answer 2

Area of floor = 6m x 4m

= 24m^2

24m^2 = 240000cm^2

240000/400 = 600 tiles.

It will require 600 x

400cm^2 tiles to cover the floor.

Hope this helps :-)