Math, asked by ltrintu6968, 11 months ago

How many tiles , each 25 cm by 20 cm , are required for the floor of a room , 12m long and 9m wide ?

Answers

Answered by ashokgmailcom
28

Answer:

2160

Step-by-step explanation:

Number of tiles = area of floor/ area of a tile

= 1200 * 900 / 25 * 50

= 2160

Answered by wifilethbridge
50

2160 tiles are required to cover floor

Step-by-step explanation:

Length of tile = 25 cm

Breadth of tile = 20 cm

Area of tile = Length \times Breadth = 25 \times 20 = 500 cm^2

1 m = 100 cm

Length of floor = 12 m = 1200 cm

Breadth of floor = 9m = 900 cm

Area of floor =Length \times Breadth = 1200 \times 900 =1080000

No. of tiles required = \frac{1080000}{500}=2160

Hence 2160 tiles are required to cover floor.

#Learn more:

A floor 8m 20cm by 6m is to be covered with tiles of size 20cm by 15cm.find the number of tiles required and the total cost of the tiles if the tiles come at Rs240 per 15 tiles

https://brainly.in/question/1734173

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