Question

how many tiles each measuring 3 metre by 15 M are required to cover a rectangular hall 18m long and 5m broad find the cost of the tiles at rupees 38 pee rile

Answer 1

Area of one tile
$=( 3 \times 15) \ {m}^{2} \\ area \: of \: hall = (18 \times 5) {m}^{2} \\ no. \: tiles \: required = \frac{18 \times 5}{3 \times 15} = 2 \\ hence \: the \: no. \: tiles \: required = 2$
Total cost of the tiles = 2 × 38 = 76
=Rs. 76

Answer 2

Answer:

The answer is Rs. 76

Step-by-step explanation:

To do this sum compare the areas of the space and the tile

the area of tile = L*B

                         =  3*15 = 45m

the area of the rectangular hall = 18*5

                                                     = 90m

no. of tiles that can fit in the hall = area of hall / area of tile

                                                     =  90/45   =  2

cost of total tiles =  no. of tiles * cost of one tile

                            =  2* 38  = Rs 76.