Math, asked by yadavbasu437, 10 months ago

how many tiles each measuring 4m by 2.5m are required to cover a rectangular room whose length and breadth are 45m and 22m respectively find the cost of tiels At ₹35 per tile?​

Answers

Answered by sherlock611holmes
1

Area of the room= 45×22 =990 m2

Area of 1 tile =4×2.5= 10 m2

No.of tiles required = area of the room / area of one tile

=99 tiles

Cost per tile= Rs.35

Cost of 99 tiles = 99×35= Rs.3465

Answered by gauravroy810
0

No.of tiles =

Area of room/Area of tile= 45x22/4x2.5

990/10=99 tiles

Cost = 99x35= Rs.3465 Ans....

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