How many tiles,each of length 8 cm and 5 cm,are needed to tile the floor of a dining space 400 cm long and 200 cm wide
Answers
Answered by
6
Area of 1 tile = 8 x 5 = 40 cm^2
Area of dining hall = 400 x 200
= 80000 cm^2
No. of tiles = 80000/40
= 8000/4 = 2000
2000 tiles are required
Area of dining hall = 400 x 200
= 80000 cm^2
No. of tiles = 80000/40
= 8000/4 = 2000
2000 tiles are required
Answered by
3
NUMBER OF TILES =
AREA OF FLOOR ÷ AREA OF EACH TILE
THEREFORE,
NUMBER OF TILES = 400 × 200 ÷ 8 × 5
= 400 × 200 ÷ 40
= 10 × 200
= 2000
THEREFORE 2,000 IS THE NUMBER OF TILES.
HOPE THIS HELPS !
AREA OF FLOOR ÷ AREA OF EACH TILE
THEREFORE,
NUMBER OF TILES = 400 × 200 ÷ 8 × 5
= 400 × 200 ÷ 40
= 10 × 200
= 2000
THEREFORE 2,000 IS THE NUMBER OF TILES.
HOPE THIS HELPS !
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