Math, asked by Ezna, 1 year ago

How many tiles of 40 cm square each will be required to pave a footpath 1 m wide carried round outside of a grassy plot 28 by 18 m

Answers

Answered by Hasti152002
27
Hey.. I think this can be ur answer!!

Area of grassy plot = 28*18 = 504 m2

Now area of bigger plot = 30*20 = 600m2

Area of footpath round plot = 600-504 = 96 m2

Area of one tile = 40*40=1600cm2 = 0.16m2

Now tiles required to pave the footpath = 96 / 0.16 = 600 tiles

SO, 600 tiles are required!!
Hope it helps you dear ☺️☺️
Have a good day!!
Attachments:

Raghav3333: it is wrong
Raghav3333: 96 / 0.16 is not 60 but 600
Hasti152002: ohh ya... sry... let me edit my answer.. and th@nks :)
Answered by Raghav3333
16
hye

============================

measures of the grassy plot = 28 by 18 m

     area = l *b

=> 28*18

=> 504  m
²

there is im path outside it 

so lenght of plot  including path = 28+1+1 = 30

breath  of plot  including path = 18+1+1 = 20

area of  plot  including path = length *breadth 

                                              = 30*20

                                               = 600 m²

area of path = area of  plot  including path -area of  plot  

                      = 600 - 504

                       = 96 m²

                         = 960000cm

now  we have to find how many tiles of 40 cm square each will be required to pave a footpath

area of tile = side *side
       
 = 40 *40

 =1600cm

=>no.of tiles= 960000/1600

                      =  600 tiles

============================

hope it helps u...............


Ezna: Thnx for your answer ☺
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