how many tiles of area 15cmsquare will be needed to cover a floor 5.85 m by 6.90m
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Answered by
0
5.85m=>585cm
6.90m=>690cm
Area=585×690=>403650cm²
Tiles required=403650/15
Tiles=26910
6.90m=>690cm
Area=585×690=>403650cm²
Tiles required=403650/15
Tiles=26910
Answered by
13
Answer
26910
step by step deviation
In the questions given data ,
A floor of length 5.85 m . and the breadth of the floor is 6.90 m.
here we find how many tiles of area 15cmsquare will be needed to cover a floor = ?

so it's first step Given data in meter its should be changed in meter.
1 meter equal to 100 cm
then , 5.85 m equal 585cm.
Next ,
since 6.90 cm equal to 690m
area of the floor = l × b
using formula = l× b
l = length
b= breadth
now we find area of floor
area of the floor = l × b

Tiles required equal to

be brainly
26910
step by step deviation
In the questions given data ,
A floor of length 5.85 m . and the breadth of the floor is 6.90 m.
here we find how many tiles of area 15cmsquare will be needed to cover a floor = ?
so it's first step Given data in meter its should be changed in meter.
1 meter equal to 100 cm
then , 5.85 m equal 585cm.
Next ,
since 6.90 cm equal to 690m
area of the floor = l × b
using formula = l× b
l = length
b= breadth
now we find area of floor
area of the floor = l × b
Tiles required equal to
be brainly
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