Question

How many tiles of dimension 10 square inch are required to cover a floor of dimension of 5 feet by 4 feet​

Answer 1

Answer:

108

Step-by-step explanation:

THE DIMENSION OF 1 TILE -10

THEN THE AREA OF 1 TILE-10×10

HENCE,AREA OF FLOOR-6 ×12+5×12-108

HENCE TILES REQUIRED-108÷10×10-108

Answer 2

288 tiles of dimension 10 square inch are required.

Step-by-step explanation:

Consider the provided information.

The dimension of floor is 5 feet by 4 feet​.

1 feet = 12 inches

Thus, 5 feet = 60 inches and 4 feet = 48 inches

Calculate the area of the floor by using the formula: $A=l\times b$

Substitute the respective values in the above formula.

$A=60\times 48$

$A=2880$

Thus, the area of the floor is 2880 inch².

Now divide the area of floor with the area of tiles.

So total number of tiles required = $\frac{2880}{10}=288$

Hence, 288 tiles of dimension 10 square inch are required.

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