Math, asked by looksd55, 11 months ago

How many tiles of dimension 10 square inch are required to cover a floor of dimension of 5 feet by 4 feet​

Answers

Answered by rocksyaduvanshi
17

Answer:

Step-by-step explanation:

28.8 or 29

Answered by ankurbadani84
14

Answer:

288 tiles

Step-by-step explanation:

Converting everything into inches.

1 feet = 12 inches

Dimensions of floor = 5 feet x 4 feet​

Dimensions of floor = (5 x 12) inches x (4 x 12) inches = 2880 inch²

Dimension of tile = 10 inch²

So total number of tiles required = 2880/10 = 288

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