Question

how many tiles of dimensions 24 cm ×15 cm will be required to cover a floor 18m long and 12 m wide?​

Answer 1

Answer:

6000

Step-by-step explanation:

First find the area of tile and that of the floor also

area of tile=24×15

=360 cm²

area of floor=1800×1200 cm²

no. of tiles required

=area of floor/area of tiles

=1200×1800/360

=1200×5

=6000

6000 tiles are required to cover the floor

Answer 2

$\bf{\boxed{\huge{\pink{Answer:6000}}}}$

Step-by-step explanation:

Given:-

Dimensions of tile-

• 24 cm

• 15 cm

Dimensions of floor-

• 18 m = 1800 cm

• 12 m = 1200 cm

To find :-

The number of tiles required to cover the floor.

Solution:-

We are using the formula for area of rectangle as the floor is rectangular in shape (Since, dimensions of the floor are unequal)

Area of floor = Length×Breadth

= (1800 × 1200) cm²

= 2160000 cm²

Since, the tile is also rectangular.

Since, the tile is also rectangular.Area of the tile = length × breadth

= (24 × 15) cm²

= 360 cm²

Now,

Number of tiles required to cover the floor = Area of floor/Area of a tile

= 2160000 cm²/ 360 cm²

= 6000 tiles.

Hence, 6000 tiles of dimension (24×15) cm² are required to cover the floor of dimension (1200×1800) cm²

__________________________

Thanks :D