Math, asked by anitaahuja18, 11 months ago

How many tiles of dimensions 24cm×15cm will be required to cover a floor 18m long and 12m wide

Answers

Answered by Anonymous
0

Answer:

600

Step-by-step explanation:

area of tile = 24*15= 360 cm square=0.0360 metre square

area of floor = 12*18= 216 metre square

number of tiles= 216/0.036 = 6000

Answered by aayushibhimjiani
0

Answer:


Area of 1 tile = l×b =24×15 =360 cm^2

Area of floor = l × b = 1800 × 1200

( conversion of metres to centimetres

1 m = 100 cm)

= 2160000 cm^2

Number of tiles required = Area of floor / Area of 1 tile

= 2160000/360 =6000 tiles



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