Math, asked by tanish12280, 4 months ago


How many tiles of length 12 cm and breadth 6 cm
can fit on a reclangular floor of length ₹ 88 cm
breadth 72 cm



please tell?​

Answers

Answered by TwilightShine
5

Question :-

How many tiles of length 12 cm and breadth 6 cm can fit on a rectangular floor of length 88 cm and breadth 72 cm?

Answer :-

  • 88 tiles of length 12 cm and breadth 6 cm can fit on a rectangular floor of length 88 cm and breadth 72 cm.

Given :-

  • Length of the tile = 12 cm.
  • Breadth of the tile = 6 cm.

To find :-

  • The number of tiles which can fit on a rectangular floor of length 88 cm and breadth 72 cm.

Step-by-step explanation :-

  • To find the number of tiles which can fit on a rectangular floor of length 88 cm and breadth 72 cm, let's find the area of each tile first.

  • The tile is in the shape of a rectangle, since it's length and breadth is given.

  • So, to find the area of the tile, we are going to use the formula required for finding the area of a rectangle.

We know that :-

 \underline{\boxed{\sf Area  \: of  \: a \:  rectangle = (Length \times  Breadth)}}

Here,

  • Length of the tile = 12 cm.
  • Breadth of the tile = 6 cm.

Hence,

 \tt Area  \: of  \: each  \: tile  = 12  \: cm \times 6 \: cm

  • Multiplying the numbers,

 \underline {\boxed{\tt Area  \: of \:  each \:  tile = 72 \: cm^2.}}

  • Now, since we know the area of each tile, therefore let's find the area of the rectangular floor.

  • The floor is in the shape of a rectangle, since it's a rectangular floor.

  • So, to find the area of the floor, we are going to use the formula required for finding the area of a rectangle.

As given above,

  \underline{\boxed{\sf Area  \: of \:  a \:  rectangle = Length  \times Breadth.}}

Here,

  • Length = 88 cm.
  • Breadth = 72 cm.

Hence,

\tt Area  \: of  \: the \:  floor = 88  \: cm \times 72  \: cm

  • Multiplying the numbers,

  \underline{\boxed{\tt Area  \: of  \: the \:  floor =6336 \: cm^2.}}

Now,

 \underline{\boxed{\sf No. \:  of \:  tiles \: needed= {\dfrac{Area  \: of \: the \: floor}{Area  \: of  \: each \: tile}}}}

  • Substituting the values in the given formula,

 \sf No. \:  of \:  tiles \: needed =  \dfrac{6336}{72}

  • Dividing 6336 by 72,

 \underline {\boxed{ \sf No. \:  of \:  tiles \: needed = 88.}}

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