Question

How many tiles of size 10 cm x 20 cm
are required to cover two sides of wall 4
m and 2 m long?​

Answer 1

Answer:

The Answer is 800 tiles

Step-by-step explanation:

Area of wall= 4*2= $8m^{2}$ = 8*100*100= 80000$cm^{2}$

Area of one tile= 10*20= 200$cm^{2}$

Area of two sides of wall= 2*80000= 160000$cm^{2}$

No. of tiles= Area of two sides of wall/ area of one tile.

= 160000/200= 800

The no. of tiles required= 800

Answer 2

Answer:

ok ok ok

Step-by-step explanation:

ok this is the answer