how many tiles whose lenght and breadth are 12cm and 5cm will be needed to cover a rectangular region whose length and breadth are respectively :i) 70cm and 36cm ii) 144cm and 1m ?
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Answer:
area of 1 tile = l*b
=12*5
=60cm
i)70cm and 36cm
area of region = l*b
=70×36
=2520cm^2
no. of tiles required = area of region ÷ area of 1 tile -------->formula
∴no. of tiles =2520/60
=42 tiles
ii) 144cm and 1m
=144cm and 100cm [∵1m = 100cm]
area of region = l*b
=144×100
=14400cm^2
no. of tiles required = area of region ÷ area of 1 tile -------->formula
∴no. of tiles = 14400/60
=240 tiles
Step-by-step explanation:
samaira260:
thanks
Can I know in which class do you study
why do u want
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1
Answer:
njbjjj is answer
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