Question

How many tiles whose length and breadth are 10 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
(a) 40 cm and 20 cm

(b) 70 cm and 60 cm​

Answer 1

Answer:

a)16 tiles required

b) 84 tiles required

Step-by-step explanation:

According to the information provided in the question it is given as

length of tiles = l = 10cm

Breadth of tiles = b=5cm

We need to find the number of tiles required for

(a) 40 cm and 20 cm

(b) 70 cm and 60 cm

First finding the size of 1 tiles

$A =l\times b\\A= 10\times 5\\A =50cm^{2}$

a) l=40cm ,b=20cm

so Area

$A =40\times 20\\A=800cm^{2}$

b) l=70cm ,b =60cm

So Area

$A =70\times 60\\A = 4200cm^{2}$

So tiles for (a)region =

$=\frac{800}{50} \\=16 Tiles$

Tiles for (b) region=

$=\frac{4200}{50} \\= 84 Tiles$

Hence

a)16 tiles required

b) 84 tiles required

Answer 2

Answer:

a)16 tiles required

b) 84 tiles required

Step-by-step explanation:

According to the information provided in the question it is given as

length of tiles = l = 10cm

Breadth of tiles = b=5cm

We need to find the number of tiles required for

(a) 40 cm and 20 cm

(b) 70 cm and 60 cm

First finding the size of 1 tiles

\begin{gathered}A =l\times b\\A= 10\times 5\\A =50cm^{2}\end{gathered}

A=l×b

A=10×5

A=50cm

2

a) l=40cm ,b=20cm

so Area

\begin{gathered}A =40\times 20\\A=800cm^{2}\end{gathered}

A=40×20

A=800cm

2

b) l=70cm ,b =60cm

So Area

\begin{gathered}A =70\times 60\\A = 4200cm^{2}\end{gathered}

A=70×60

A=4200cm

2

So tiles for (a)region =

\begin{gathered}=\frac{800}{50} \\=16 Tiles\\\end{gathered}

=

50

800

=16Tiles

Tiles for (b) region=

\begin{gathered}=\frac{4200}{50} \\= 84 Tiles\end{gathered}

=

50

4200

=84Tiles

Hence

a)16 tiles required

b) 84 tiles required

Step-by-step explanation:

Hope it helps you

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