Question

How many tiles whose length and breadth are 10 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
(a) 40 cm and 20 cm

(b) 70 cm and 60 cm ​

Answer 1

Answer:

a)16 tiles required

b) 84 tiles required

Step-by-step explanation:

According to the information provided in the question it is given as

length of tiles = l = 10cm

Breadth of tiles = b=5cm

We need to find the number of tiles required for

(a) 40 cm and 20 cm

(b) 70 cm and 60 cm

First finding the size of 1 tiles

A =l\times b\\A= 10\times 5\\A =50cm^{2}

a) l=40cm ,b=20cm

so Area

A =40\times 20\\A=800cm^{2}

b) l=70cm ,b =60cm

So Area

A =70\times 60\\A = 4200cm^{2}

So tiles for (a)region =

=\frac{800}{50} \\=16 Tiles\\

Tiles for (b) region=

=\frac{4200}{50} \\= 84 Tiles

Hence

a)16 tiles required

b) 84 tiles required

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Answer 2

$No. \: of \: Tiles = \frac{Area \: of \: Region }{Area \: of \: 1 \: tile }$

$1) = \frac{40 \times 60}{10 \times 5}$

$= 48 \: tiles$

$2) = \frac{70 \times 60}{10 \times 5}$

$= 84$