Question

How many tiles whose length and breadth are 10cm and 4cm respectively will be needed

to fit in a rectangular region whose length and breadth are respectively 100cm and

20cm ?

some one please answer in full method as a humble request​

Answer 1

Answer:

Area of rectangle = L × B

= 10 × 4

= 40 cm

Area of rectangular region = L × B

= 100 × 20

= 2000 cm

Tiles needed = 2000 ÷ 40

= 500 tiles

Answer 2

$\large\mathfrak \blue{Solution:-}$

$\underline \mathbb{GIVEN:-}$

★Length and breadth of the tiles 10 cm and 4 cm respectively.

★Length and breadth of the rectangular region 100 cm and 20 cm respectively.

$\underline \mathbb{TO \: FIND:-}$

How many tiles required to cover the whole region?

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

$Number \: of \: tiles = \frac{Total \: area \: of \: the \: rectangular \: region}{ Area \: of \: each \: tiles} \\ \\ \implies \: Number \: of \: tiles = \cancel\frac{100 \times 20}{10 \times 4} \\ \\ \implies \: Number \: of \: tiles =50$

$\underline \mathbb{ANSWER:-}$

50 tiles required to cover the whole region.