Math, asked by mahimamahi49187, 4 days ago

How Many tiles whose length and breadth are 12 CM respectively Will be needed to cover a rectangular region whose length and breadth are respectively:
(i) 70cm and 36 CM
(ii) 144cm and 1 CM ​

Answers

Answered by at9738122
0

Answer:

Step-by-step explanation:

(a) Area of rectangular region = 100 × 144

= 14400 cm

Also, area of one tile = 5 × 12

= 60 cm2

The number of tiles needed = Area of the rectangular region / Area of one tile

= 14400 / 60

= 240

Hence, 240 tiles are needed in this case.

(b) Now, area of rectangular region = 70 × 36

= 2520 cm2

Also, area of one tile = 5 × 12

= 60 cm2

The number of tiles needed = Area of the rectangular region / Area of one tile

= 2520 / 60

= 42

Hence, 42 tiles are needed in this case.

Therefore, 240 tiles are required in 1st case and 42 tiles are required in 2nd case.

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Answered by pavneet06
0

Answer:

☆ 18 tiles

Step-by-step explanation:

i) Length of the rectangular region = 70 cm

Breadth of the rectanguler region = 36 cm

Area = l × b

= 70 × 36

= 2520 cm²

Side of tile = 12 cm

Area = side × side

= 12 × 12

= 144 cm ²

No. of tiles needed = 2520 ÷ 1 44

= 17.5

= 18 (approx.)

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