Math, asked by xXitzQueenofDpXx, 5 months ago

✎ How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit and a rectangular reason length and breadth are respectfully 200 and 144 CM.



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Answers

Answered by MoodyCloud
59
  • 450 tiles are required.

Step-by-step explanation:

Given that,

Length and breadth of one tile is 12 cm and 5 cm respectively.

Length and breadth of rectangular region is 200 cm and 144 cm respectively.

For tile :-

Length of tile = 12 cm.

Breadth of tile = 5 cm.

For rectangular region :-

Length of rectangular region = 200 cm.

Breadth of rectangular region = 144 cm.

  • For finding tiles first we need area of tile and area of that region for tiles are required.

If length and breadth of tile is given. So, Tile is of rectangular shape.

Area of rectangle = Length × Breadth

Area of tile :-

 \longrightarrow 12 × 5

  \longrightarrow 60

Area of one tile is 60 cm².

Area of rectangular region :-

 \longrightarrow 200 × 144

  \longrightarrow 28800

Area of rectangular region is 28800 cm².

_______________________________

Number of tiles = Area of rectangular region/Area of one tile.

 \longrightarrow  \sf \cfrac{28800}{60}

 \longrightarrow  \sf 480

Therefore,

Total number of tiles required to cover rectangular region having length and breadth be 200 cm and 144 cm is 450 tiles.

Answered by Anonymous
48

Answer:

 \huge \bf \: given

  • Length of tile = 12 cm
  • Breadth of tile = 5 cm
  • Length of floor = 200 cm
  • Breadth of floor = 144 cm

 \huge \bf \: to \: find

Tiles required

 \huge \bf \: solution

 \sf \: in \: this \: we \: have \: to \: find \: the \: area \:  \\  \sf \: of \: the \: floor \: and \: the \: tile

 \sf \: as \: we \: know \: that

 \huge \bf \: area \small \bf \: (rectangle) =\huge \bf  l \times b

 \sf \: area \: of \: one \: tile = l \:  \times b

 \sf \: area \: of \: 1 \: tile \:  = 12 \times 5

 \sf area \: of \: 1 \: tile \:  =  {60 \: cm}^{2}

 \sf \: now \: finding \: area \: of \: floor

 \sf \: area \: of \: floor \:  = l \:  \times b

 \sf \: area \: of \: floor \:  = 200 \times 144

 \sf \: area \: of \: floor \:  =  {28800 \: cm}^{2}

 \bf \: tiles \: \: required \: =   \frac{area \: of \: floor}{area \: of \: 1 \: tile}

 \sf \: tiles \: required \:  =  \frac{28800}{60}

 \sf \: tiles \: required \:  = 480 \: tiles

Total tiles = 480

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