Math, asked by arvindkpandey10, 3 months ago

How many tiles whose length and breadth are 12cm and 10cm respectively

will be needed to fit in a rectangular region whose length and breadth are 4m

and 3m respectively. Also, find the total cost of the tiles at the rate of Rs 5

per tile.
pl answer
really urgent

Answers

Answered by adiha1505
1

Answer:

no of tiles needed = 1000

total cost of tiling = ₹6,00,000 ( 6 lakh rupees)

Step-by-step explanation:

area of tiles = L× B = 12 × 10 = 120 cm²

area of region = l×b = 12m² = 120000cm²

therefore no of tiles needed =

area of region / area of tiles

= 120000/120

= 1000

1000 tiles are needed to fit the area completely

Rate of tiling = ₹5 / cm²

total cost of tiling = 5 × 120000

= 6,00,000

Answered by ishanyakiritjain
1

Answer:

Step-by-step explanation:

Tiles length= 12cm

Tiles breadth= 10cm

Area of one tiles= l×b= 12 × 10= 120cm sq.=

Rectangular region's length= 4m

rectangular region's breadth= 3m

Area of rectangular region= l×b= 4×3= 12m

Now,

1m = 100cm

1.20m= 120cm

No. of tiles that can fit= 12m/1.20m= 10 tiles

Cost of one tile= Rs.5

Cost of 10 tiles= 5×10= Rs.50

Therefore, 10 tiles can fit in the rectangular region at the rate of Rs. 50

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