How many tiles whose length and breadth are 12cm and 5cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively.
a) 100cm and 144cm b) 70cm and 36ccm.
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Firstly find the area of tiles.
2×(12+5)=34cmsq
then find the area of first rectangular region.
22×(100+144)=488cmsq
and also find the area of second rectangular region.
2×(70+36)=212cmsq
no. tiles in first rectangular region =488×34=16592 tiles.
and no. of tiles in second rectangular region =212×34=7208 tiles.
2×(12+5)=34cmsq
then find the area of first rectangular region.
22×(100+144)=488cmsq
and also find the area of second rectangular region.
2×(70+36)=212cmsq
no. tiles in first rectangular region =488×34=16592 tiles.
and no. of tiles in second rectangular region =212×34=7208 tiles.
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