Question

How many tiles with dimensions 14 cm and 9 cm will be needed to fit a region whose length and breadth are 168 cm and 72 cm ?

Answer 1

Answer

Dimensions of tiles=14cm*9cm

Dimensions of region =168cm*72cm

No.of tiles needed=dimensions of region/dimensions of tiles

=168*72/14*9

=12*8

=96 tiles

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Answer 2

96 tiles are required

Step-by-step explanation:

Length of floor = 168 cm

Breadth of floor = 72 cm

Area of floor = $Length \times Breadth = 168 \times 72 = 12096 cm^2$

Length of tile = 14 cm

Breadth of tile = 9 cm

Area of 1 tile =$Length \times breadth = 14 \times 9 = 126 cm^2$

No. of tiles are required = $\frac{12096}{126}=96$

Hence 96 tiles are required

#Learn more:

The length and breadth of a room are 434 cm and 306 cm respectively. The dimensions of a tile are 14 cm by 9 cm. How many of such tiles are needed to tile the room ?

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