Question

how many tiles with length and breadth as 21/5 m and 10/3 m respectively are required to cover the rectangular floor whose length and breadth are 117/8 m and 112/3 m respectively?​

Answer 1

Solution :-

The length and breath of the rectanglular floor are 117/8m and 112/3 m

Therefore,

Area of the floor = Length * Breath

Subsitute the required values,

Area of the floor

= 117/8 * 112/3

= 39 * 14

= 546m²

Thus, The area of the floor is 546m^2

Now,

The length and breath of the tile is 21/5m and 10/3m

Therefore,

Area of one tile = Length * Breath

Subsitute the required values,

Area of one tile

= 21/5 * 10/3

= 7 * 2

= 14m²

Thus, The area of one tile is 14m²

Now, We have to cover the floor with tiles

Let the number of tiles be n

Therefore,

n = Area of floor / Area of one tile

n = 546 / 14

n = 39

Hence, The number of tiles required to cover the floor are 39$.$