Question

How many times do you expect to get 4 when a die is thrown 90 times

Answer 1

Answer:

1/6×90=1/15

Explanation:

probability of coming 4 in one times will be 1/6

then in 90 times it will be 1/6×90

Answer 2

4 would be expected to come up in one sixth of the trial, so 4 in 90 roll will be 15 times is the probability.

Explanation: Let X be the number of 4 rolled in 90 times, then to find the value of X, the distribution parameter p and n.

• p = probability of rolling 4 = 1÷6

• n = number of trials = 90
• Expected out come (x) = p*n = $\frac{1}{6}*90$ = 15
• So 15 will be the probability of 4 rolling 90 times