How many times does Shibani have to run around the field 83m and 33m wide to cover 928m?
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Answer:
dimensions of the field :
l = 83 m
b = 33 m
Perimeter = 2 ( l+b )
= 2 ( 83 + 33 )
= 2 ( 116 )
= 232 m
Lets take the no of times she runs around it as x
x = 928 / 232
= 4
Hence , she has to run around the field 4 times .
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