Question

how many times does the digit 3 occurs at tens place in natural numbers from 100 to 1000​

Answer 1

Answer:

Number of ways X can be filled = 9 (1–9 numbers excluding 0 as it is a 3 digit number). So, number of times 3 occurs in ten's and unit's place from 100 to 1000 = 90+81 = 171

Answer 2

Answer:

Number of ways X can be filled = 9 (1–9 numbers excluding 0 as it is a 3 digit number). So, number of times 3 occurs in ten's and unit's place from 100 to 1000 = 90+81 = 171.

Step-by-step explanation:

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